The Laplace transform of exp(at), where a > 0, is defined only for the Laplace parameter, s > a since______________?

A. The Laplace transform of integral of exp(at) has finite values only for s > a

B. The function exp(at) is piece-wise continuous only for s > a

C. The Laplace transform integral of exp(at) has initial values only for s > a

D. The function is exponential

Found an error? Read our corrections policy and submit a sourced correction below. You can also share a useful explanation in your own words.

Discuss the answer or suggest a sourced correction
Thank you for contributing.
Your comment was submitted and will appear after editorial review.

Your email is used only for moderation and is never displayed. Spam, copied material and fabricated endorsements are rejected.