A. change in volume to original volume

B. none of the above

D. change in length to original length

E. change in cross-sectional area to original cross-sectional area

B. none of the above

C. successfully constrained motion

D. completely constrained motion

E. partially constrained motion

B. same

C. more or less depending on ambient conditions

D. unpredictable

E. more

A. condenser

B. compressor

C. evaparator

E. heat transfer

A. none of the above

B. cor, 0

C. 0, and less than coV

D. 0, 0

B. none of the above

C. from minimum at the centro to maxi-mum at the circumference

D. from maximum at the center to mini-mum at the cricumference

E. from maximum at the center to zero at the circumference

A. near critical pressure

B. there is no such restriction

C. critical pressure of refrigerant

D. much above critical pressure

A. none of the above

B. pair of clinical tongs

C. arm of man

D. pair of scissors

A. is equal to 1

C. is less than 1

D. depends upon the weather conditions

E. depends upon the make

A. none of the above

C. Inertia governor

D. Wilson Hartnell governor

E. Hartung governor

A. mechanical advantage is greater than velocity ratio

B. mechanical advantage is equal to velocity ratio

C. none of the above

D. mechanical advantage is unity

A. 3r/8

B. r/%

C. r/A

D. r/2

A. number of cycles it undergoes before failure

B. maximum torque it can transmit

D. maximum power it can transmit at highest possible-speed

E. elastic limit up to which it resists torsion, shear and bending stresses

A. none of the above

B. is same as that of velocity

D. is opposite to that of velocity

E. is perpendicular to that of velocity

A. 15%

B. 50%

D. 60%.

E. 25%

A. turning pair

C. rotary pair

D. sliding pair

E. higher pair

A. square

B. rectangle

D. equilateral triangle

E. circle

A. broken belt

B. broken belt and its adjacent belts

C. all the weak belts

D. there is no need of changing any one as remaining belts can take care of transmission of load

A. equal

C. smaller/bigger depending on capacity

D. unpredictable

E. smaller

A. lesser than that necessary to stop it

B. considerably lesser than that necessary to continue it

C. greater than that necessary to stop it

D. equal to that necessary to stop it

B. P = 2L-4

C. P = L-4

D. P = 2L + 4

E. P = 2L-2

A. increase key depth

B. none of the above

C. increase key length

E. double all the dimensions

A. unit strain

B. linear stress

C. strain

E. lateral strain

A. 3 links with pin joints

B. all of the above

C. 1 link with pin joints

E. 2 links with pin joints

A. creep

B. frequent heat treatment

C. resonant condition

E. fatigue

A. unpredictable

C. remain unaffected

D. decrease

E. may increase or decrease depending on the type of refrigerant used

A. depends on other factors

B. remains same

D. none of the above

E. decreases

A. at which all the three phases exist together

B. above which liquid becomes vapour

C. above which liquid becomes gas

E. above which liquid becomes solid

A. lower than atmospheric pressure

C. could be anything

D. none of the above

E. equal to atmospheric pressure

A. average of the sum of moduli of elas-ticity

B. none of the above

C. inversely proportional to their moduli of elasticity

E. equal

A. all of the above

B. to control

C. none of the above

D. decrease the variation of speed

A. is based on acceleration diagram

B. is a simplified form of instantaneous center method

C. none of the above

D. enables determination of Coriolis component

A. lateral stress and lateral strain

C. shear stress to shear strain

D. longitudinal stress and lateral strain

E. volumetric stress and volumetric strain

A. none of the above

C. mutter gears

D. double helical gears having identical teeth

E. single helical gear in which one of the teeth of helix angle a is more

A. none of the above

B. parabola

C. circle

E. ellipse

A. Knuckle joint

C. bevel gear

D. Oldhams coupling

E. universal joint

A. have surface contact

B. have line contact

D. are held together

E. have dynamic forces

A. euqal

B. high

C. under some conditions small and under some conditions high

E. anything

A. sliding pair

B. surface pair

C. rolling pair

E. lower pair

B. one fork

C. five forks

D. three forks

E. four forks

B. none of the above

C. reduce compressor overheating

D. increase cooling effect

E. reduce compressor discharge temperature

A. ultimate tensile stress

C. yield point stress

D. fracture stress

E. proof stress

A. chain coupling

B. flexible coupling

C. Oldhams coupling

E. American coupling

A. load/original cross-sectional area and change in length/original length

B. load/instantaneous area and instantaneous area/original area

D. none of the above

E. load/instantaneous cross-sectional area and change in length/original length

A. fourth inversion of double slider crank chain

B. third inversion of slider crank chain

C. second inversion of double slider crank chain

E. second inversion of single slider crank chain

A. Simplex indicator

B. none of the above

C. Thompson indicator

E. Thomson indicator

A. none of the above

B. support is frictionless

D. support can take any amount of reaction

E. support holds member firmly

A. extreme value

B. maximum calculated value

C. none of the above

E. mean value

A. hyperbola

B. elliptical

D. straight line

E. part of a circle

B. constant

C. both of above are correct

D. both of above are wrong

E. none of the above